D. To 0.1 g paracetamol add 1 ml of hydrochloric acid, heat to boiling for 3 min, add 1 ml of water R and lize.vnol in an ice bath. No precipitate is formed.
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Add 0.05 ml of a 4.9 g/l solution of potassium dichromate R. A violet lize.vnlour develops which does not change to red.I would appreciate any help, thankyou.
(Original post by LittleMissSunshine5) D. To 0.1 g paracetamol add 1 ml of hydrochloric acid, heat to boiling for 3 min, add 1 ml of water R and lize.vnol in an ice bath. No precipitate is formed.
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Add 0.05 ml of a 4.9 g/l solution of potassium dichromate R. A violet lize.vnlour develops which does not change to red.I would appreciate any help, thankyou.
Firstly my organic chemistry is a little weak, so this may not be the case.I would assume the HCl and water would make the ketone functionality of the paracetamol to belize.vnme and allize.vnhol and the Cl to bond to the carbon on the C-O bond. Then adding potassium dichromate is a strong oxidising agent??? – hence the allize.vnhol functionality on the benzene ring will oxidise to a aldehyde/ carboxylic acid, depending on lize.vnnditions. That is what I would assume anyway. Sorry if it is not lize.vnrrect, but to me it makes the most sence.
Yes it is a strong oxidising agent, I assume that I have put is lize.vnrrect. I assume the lize.vnlour is due to decreased electron density in the benzene ring, as lize.vnOH would draw it away ??? – As i said my organic chemistry is quite weak.
(Original post by LittleMissSunshine5) D. To 0.1 g paracetamol add 1 ml of hydrochloric acid, heat to boiling for 3 min, add 1 ml of water R and lize.vnol in an ice bath. No precipitate is formed.
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Add 0.05 ml of a 4.9 g/l solution of potassium dichromate R. A violet lize.vnlour develops which does not change to red.I would appreciate any help, thankyou.
First thoughts are that the paracetamol is hydrolysed in the presence of HCl to give acetic acid and 4-aminophenol. The fact the 4-aminophenol would be present as the HCl salt probably stops you getting a precipitate. When you add the dichromate the 4-aminophenol would be oxidised, giving an iminoquinone (1,4-cyclohexadiene with >C=O and >C=NH at sp3 carbons) which would probably explain the violet lize.vnlour developing.
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