Balance This Chemical Equation, Fes2 + O2 → Fe2O3 + So2, Fes2 + O2 = Fe2O3 + So2

Fe2O3 + SO2Now,u00a0In reactant side,Fe = 1S = 2O = 2In product side,u00a0Fe = 2S = 1O = 3+2 = 5None is balancedu00a0Let us take Fe.In reactant side 1 and product side 2.Thus, add 2 before Fe in reactant side.Now we have,u00a02 FeS2 + O2 —> Fe2O3 + SO2Now, Fe balanced.In reactant side,S = 4O = 2In product side,S = 1O = 5Now, let us balance S.We have 4 S in reactant side and 1 S in product side.Add 4 before S in product sideu00a0Now we have the equation,2 FeS2 + O2 —> Fe2O3 + 4 SO2Now, Fe and S are balanced.Now, let us balance O.In reactant side we have 2 and in product side we have 11O is odd in product side. As balancing is hit and trial method let us use one trick. Whenever we get stuck like this, make the odd thing even.So, add 2 before Fe2O3.Now,2 FeS2 + O2 —> 2 Fe2O3 + SO2u00a0Now, we have 2 Fe in product side and 4 Fe in reactant side. So, add 2 before FeS2.u00a0Thus, 2+2 FeS2 = 4 FeS2Now,u00a04 FeS2 + O2 —> 2 Fe2O3 + 4 SO2Now, we have 8 S in reactant side and 4 S in product side.

Add 4 in reactant side.4 + 4 SO2 = 8 SO2Now,4 FeS2 + O2 —> 2 Fe2O3 + 8 SO2We have 2 O in reactant side and 22 O in product side.So, 22 O = 2 u00d7 11 = 22 O.Therefore, add 11 before O2.Now the equation is,4 FeS2 + 11O2 —> 2 Fe2O3 + 8 SO2Now, let us checku00a0In reactant side,Fe = 4S = 8u00a0O = 22In product side,Fe = 4S = 😯 = 22Hence, balancedu00a0_____________________________The balanced equation:4 FeS2 + 11O2 —> 2 Fe2O3 + 8 SO2″},{“id”:9705087,”content”:”

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FeS2 + O2 —> Fe2O3 + SO2Now, In reactant side,Fe = 1S = 2O = 2In product side, Fe = 2S = 1O = 3+2 = 5None is balanced Let us take Fe.In reactant side 1 and product side 2.Thus, add 2 before Fe in reactant side.Now we have, 2 FeS2 + O2 —> Fe2O3 + SO2Now, Fe balanced.In reactant side,S = 4O = 2In product side,S = 1O = 5Now, let us balance S.We have 4 S in reactant side and 1 S in product side.Add 4 before S in product side Now we have the equation,2 FeS2 + O2 —> Fe2O3 + 4 SO2Now, Fe and S are balanced.Now, let us balance O.In reactant side we have 2 and in product side we have 11O is odd in product side. As balancing is hit and trial method let us use one trick. Whenever we get stuck like this, make the odd thing even.So, add 2 before Fe2O3.Now,2 FeS2 + O2 —> 2 Fe2O3 + SO2 Now, we have 2 Fe in product side and 4 Fe in reactant side. So, add 2 before FeS2. Thus, 2+2 FeS2 = 4 FeS2Now, 4 FeS2 + O2 —> 2 Fe2O3 + 4 SO2Now, we have 8 S in reactant side and 4 S in product side. Add 4 in reactant side.4 + 4 SO2 = 8 SO2Now,4 FeS2 + O2 —> 2 Fe2O3 + 8 SO2We have 2 O in reactant side and 22 O in product side.So, 22 O = 2 × 11 = 22 O.Therefore, add 11 before O2.Now the equation is,4 FeS2 + 11O2 —> 2 Fe2O3 + 8 SO2Now, let us check In reactant side,Fe = 4S = 8 O = 22In product side,Fe = 4S = 😯 = 22Hence, balanced _____________________________The balanced equation:4 FeS2 + 11O2 —> 2 Fe2O3 + 8 SO2

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