# Please Write Net Ionic Equations: 1) Hcl + Ag+, Ag + Hcl = Agcl + H2

⇒ Step 2: Compare the number of atoms of reactants with the number of atoms of products.

⇒ Step 3: Now, First we consider the element having unequal no. of atoms on both sides. Thus, let us consider hydrogen atom. If we multiply 2 in the reactant (in HCl), we will get the equal number of atoms as in product (H2)

⇒ Step 4: Write the resulting equation:

Ag + 2HCl → AgCl + H2

⇒ Step 5: Now check whether the equation is balanced or not by comparing the atoms

We find that the equation is not balanced yet. As the number of

chlorine atom is unequal on the two sides.

First balance the chlorine number.

⇒ Step 6: Now, let us consider chlorine atom. If we multiply 2 in the product (in AgCl), we will get the equal number of atoms as in reactant (in HCl)

⇒ Step 7: Write the resulting equation:

Ag + 2HCl

2AgCl + H2

⇒ Step 8: Now check whether the equation is balanced or not by comparing the atoms

We find that the equation is not balanced yet. As the number of

silver atom is unequal on the two sides.

READ:  Andehit Có Tác Dụng Với Naoh Không, Tính Chất Hóa Học Của Andehit

⇒ Step 9: Now, let us consider silver atom. If we multiply 2 in the reactant (Ag), we will get the equal number of atoms as in product (AgCl)

⇒ Step 10: Write the resulting equation:

2Ag + 2HCl

2AgCl + H2

⇒ Step 11: Now, compare the atoms of both the sides of all the elements. Write down the final balanced equation:

Xem thêm bài viết thuộc chuyên mục: Hóa học